Base | Representation |
---|---|
bin | 11101110100010111111000… |
… | …110101000110111011010101 |
3 | 122012100002111010002012022102 |
4 | 131310113320311012323111 |
5 | 114142114124221322331 |
6 | 1142525554133011445 |
7 | 36423504126050255 |
oct | 3564277065067325 |
9 | 565302433065272 |
10 | 131142411120341 |
11 | 388712032246a5 |
12 | 12860340183b85 |
13 | 58238a3ac312a |
14 | 2455480149965 |
15 | 10264ad5524cb |
hex | 7745f8d46ed5 |
131142411120341 has 2 divisors, whose sum is σ = 131142411120342. Its totient is φ = 131142411120340.
The previous prime is 131142411120311. The next prime is 131142411120401. The reversal of 131142411120341 is 143021114241131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72894284974225 + 58248126146116 = 8537815^2 + 7632046^2 .
It is a cyclic number.
It is not a de Polignac number, because 131142411120341 - 218 = 131142410858197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131142411120311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571205560170 + 65571205560171.
It is an arithmetic number, because the mean of its divisors is an integer number (65571205560171).
Almost surely, 2131142411120341 is an apocalyptic number.
It is an amenable number.
131142411120341 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142411120341 is an equidigital number, since it uses as much as digits as its factorization.
131142411120341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 29.
Adding to 131142411120341 its reverse (143021114241131), we get a palindrome (274163525361472).
The spelling of 131142411120341 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred eleven million, one hundred twenty thousand, three hundred forty-one".
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