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131142411431293 is a prime number
BaseRepresentation
bin11101110100010111111000…
…110110010010110101111101
3122012100002111010122222212011
4131310113320312102311331
5114142114124311300133
61142525554143411221
736423504131513653
oct3564277066226575
9565302433588764
10131142411431293
1138871203417289
12128603402b3b11
1358238a3ba1822
1424554801cadd3
1510264ad5b46cd
hex7745f8d92d7d

131142411431293 has 2 divisors, whose sum is σ = 131142411431294. Its totient is φ = 131142411431292.

The previous prime is 131142411431189. The next prime is 131142411431363. The reversal of 131142411431293 is 392134114241131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106211533586404 + 24930877844889 = 10305898^2 + 4993083^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131142411431293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131142411437293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571205715646 + 65571205715647.

It is an arithmetic number, because the mean of its divisors is an integer number (65571205715647).

Almost surely, 2131142411431293 is an apocalyptic number.

It is an amenable number.

131142411431293 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142411431293 is an equidigital number, since it uses as much as digits as its factorization.

131142411431293 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 62208, while the sum is 40.

The spelling of 131142411431293 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred eleven million, four hundred thirty-one thousand, two hundred ninety-three".