1311424211133 has 16 divisors (see below), whose sum is σ = 1969465079040. Its totient is φ = 862306329312.

The previous prime is 1311424211087. The next prime is 1311424211137. The reversal of 1311424211133 is 3311124241131.

1311424211133 is a `hidden beast` number, since 1 + 3 + 11 + 424 + 211 + 13 + 3 = 666.

It is not a de Polignac number, because 1311424211133 - 2⁴⁰ = 211912583357 is a prime.

It is a super-2 number, since 2×1311424211133² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 1311424211097 and 1311424211106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311424211137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 332677941 + ... + 332681882.

It is an arithmetic number, because the mean of its divisors is an integer number (123091567440).

Almost surely, 2^{1311424211133} is an apocalyptic number.

It is an amenable number.

1311424211133 is a deficient number, since it is larger than the sum of its proper divisors (658040867907).

1311424211133 is an equidigital number, since it uses as much as digits as its factorization.

1311424211133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 665359905 (or 665359899 counting only the distinct ones).

The product of its digits is 1728, while the sum is 27.

Adding to 1311424211133 its reverse (3311124241131), we get a palindrome (4622548452264).

The spelling of 1311424211133 in words is "one trillion, three hundred eleven billion, four hundred twenty-four million, two hundred eleven thousand, one hundred thirty-three".