Base | Representation |
---|---|
bin | 11101110100010111111001… |
… | …011111011101000101100111 |
3 | 122012100002111212222011202211 |
4 | 131310113321133131011213 |
5 | 114142114140042034114 |
6 | 1142525555210544251 |
7 | 36423504322313206 |
oct | 3564277137350547 |
9 | 565302455864684 |
10 | 131142422221159 |
11 | 38871209516928 |
12 | 12860343a38087 |
13 | 58238a61aba6b |
14 | 24554817d923d |
15 | 10264ae4e66c4 |
hex | 7745f97dd167 |
131142422221159 has 2 divisors, whose sum is σ = 131142422221160. Its totient is φ = 131142422221158.
The previous prime is 131142422221091. The next prime is 131142422221207. The reversal of 131142422221159 is 951122224241131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131142422221159 - 241 = 128943398965607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131142422224159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571211110579 + 65571211110580.
It is an arithmetic number, because the mean of its divisors is an integer number (65571211110580).
Almost surely, 2131142422221159 is an apocalyptic number.
131142422221159 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142422221159 is an equidigital number, since it uses as much as digits as its factorization.
131142422221159 is an evil number, because the sum of its binary digits is even.
The product of its digits is 69120, while the sum is 40.
The spelling of 131142422221159 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred twenty-two million, two hundred twenty-one thousand, one hundred fifty-nine".
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