Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …111000100101010000011 |
3 | 11122101000102101002211012 |
4 | 103011112333010222003 |
5 | 132441244121300003 |
6 | 2442243212111135 |
7 | 163514214322124 |
oct | 23052677045203 |
9 | 4571012332735 |
10 | 1311424400003 |
11 | 466198980a93 |
12 | 1921b54654ab |
13 | 96888c27443 |
14 | 4768a97204b |
15 | 241a6d978d8 |
hex | 13156fc4a83 |
1311424400003 has 2 divisors, whose sum is σ = 1311424400004. Its totient is φ = 1311424400002.
The previous prime is 1311424399981. The next prime is 1311424400113. The reversal of 1311424400003 is 3000044241131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311424400003 - 212 = 1311424395907 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311424400903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655712200001 + 655712200002.
It is an arithmetic number, because the mean of its divisors is an integer number (655712200002).
Almost surely, 21311424400003 is an apocalyptic number.
1311424400003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311424400003 is an equidigital number, since it uses as much as digits as its factorization.
1311424400003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 1311424400003 its reverse (3000044241131), we get a palindrome (4311468641134).
The spelling of 1311424400003 in words is "one trillion, three hundred eleven billion, four hundred twenty-four million, four hundred thousand, three".
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