Base | Representation |
---|---|
bin | 10011000101010111000… |
… | …001001001011011011001 |
3 | 11122101000110101201211001 |
4 | 103011113001021123121 |
5 | 132441244241200313 |
6 | 2442243231505001 |
7 | 163514222045464 |
oct | 23052701113331 |
9 | 4571013351731 |
10 | 1311424943833 |
11 | 466199212634 |
12 | 1921b5688161 |
13 | 96889087b34 |
14 | 4768aa742db |
15 | 241a6e53add |
hex | 131570496d9 |
1311424943833 has 2 divisors, whose sum is σ = 1311424943834. Its totient is φ = 1311424943832.
The previous prime is 1311424943821. The next prime is 1311424943893. The reversal of 1311424943833 is 3383494241131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1135861429824 + 175563514009 = 1065768^2 + 419003^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311424943833 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311424943893) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655712471916 + 655712471917.
It is an arithmetic number, because the mean of its divisors is an integer number (655712471917).
Almost surely, 21311424943833 is an apocalyptic number.
It is an amenable number.
1311424943833 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311424943833 is an equidigital number, since it uses as much as digits as its factorization.
1311424943833 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 746496, while the sum is 46.
The spelling of 1311424943833 in words is "one trillion, three hundred eleven billion, four hundred twenty-four million, nine hundred forty-three thousand, eight hundred thirty-three".
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