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1311425203313 is a prime number
BaseRepresentation
bin10011000101010111000…
…010001000110001110001
311122101000110212220202102
4103011113002020301301
5132441244323001223
62442243241230145
7163514224206131
oct23052702106161
94571013786672
101311425203313
1146619937a585
121921b5792355
1396889148c84
144768ab00ac1
15241a6ea5928
hex13157088c71

1311425203313 has 2 divisors, whose sum is σ = 1311425203314. Its totient is φ = 1311425203312.

The previous prime is 1311425203303. The next prime is 1311425203339. The reversal of 1311425203313 is 3133025241131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 880384370944 + 431040832369 = 938288^2 + 656537^2 .

It is an emirp because it is prime and its reverse (3133025241131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311425203313 - 222 = 1311421009009 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311425203303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655712601656 + 655712601657.

It is an arithmetic number, because the mean of its divisors is an integer number (655712601657).

Almost surely, 21311425203313 is an apocalyptic number.

It is an amenable number.

1311425203313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311425203313 is an equidigital number, since it uses as much as digits as its factorization.

1311425203313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 29.

The spelling of 1311425203313 in words is "one trillion, three hundred eleven billion, four hundred twenty-five million, two hundred three thousand, three hundred thirteen".