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131142529981 is a prime number
BaseRepresentation
bin111101000100010110…
…1000011001110111101
3110112111112210210010001
41322020231003032331
54122034441424411
6140125051314301
712321556053361
oct1721055031675
9415445723101
10131142529981
11506875a2891
12214bb44b991
13c49c7c6788
1464c11192a1
1536282eadc1
hex1e88b433bd

131142529981 has 2 divisors, whose sum is σ = 131142529982. Its totient is φ = 131142529980.

The previous prime is 131142529963. The next prime is 131142530053. The reversal of 131142529981 is 189925241131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92714769081 + 38427760900 = 304491^2 + 196030^2 .

It is a cyclic number.

It is not a de Polignac number, because 131142529981 - 27 = 131142529853 is a prime.

It is a super-2 number, since 2×1311425299812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131142529951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571264990 + 65571264991.

It is an arithmetic number, because the mean of its divisors is an integer number (65571264991).

Almost surely, 2131142529981 is an apocalyptic number.

It is an amenable number.

131142529981 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142529981 is an equidigital number, since it uses as much as digits as its factorization.

131142529981 is an evil number, because the sum of its binary digits is even.

The product of its digits is 155520, while the sum is 46.

The spelling of 131142529981 in words is "one hundred thirty-one billion, one hundred forty-two million, five hundred twenty-nine thousand, nine hundred eighty-one".