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131143121011 = 718734731573
BaseRepresentation
bin111101000100010111…
…1010011100001110011
3110112111120220210212001
41322020233103201303
54122040114333021
6140125112114431
712321564064450
oct1721057234163
9415446823761
10131143121011
1150687966941
12214bb695a17
13c49c9727b6
1464c1230827
1536283b6091
hex1e88bd3873

131143121011 has 4 divisors (see below), whose sum is σ = 149877852592. Its totient is φ = 112408389432.

The previous prime is 131143121003. The next prime is 131143121027. The reversal of 131143121011 is 110121341131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131143121011 - 23 = 131143121003 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131143121011.

It is not an unprimeable number, because it can be changed into a prime (131143121041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9367365780 + ... + 9367365793.

It is an arithmetic number, because the mean of its divisors is an integer number (37469463148).

Almost surely, 2131143121011 is an apocalyptic number.

131143121011 is a deficient number, since it is larger than the sum of its proper divisors (18734731581).

131143121011 is an equidigital number, since it uses as much as digits as its factorization.

131143121011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18734731580.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 131143121011 its reverse (110121341131), we get a palindrome (241264462142).

The spelling of 131143121011 in words is "one hundred thirty-one billion, one hundred forty-three million, one hundred twenty-one thousand, eleven".

Divisors: 1 7 18734731573 131143121011