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13114330420441 is a prime number
BaseRepresentation
bin1011111011010110101100…
…0000011001010011011001
31201102201101020100122201211
42332311223000121103121
53204331122041423231
643520350142143121
72522323222214335
oct276655300312331
951381336318654
1013114330420441
1141a68356a5878
12157978a881aa1
137418a3395c83
14334a463b07c5
1517b201a21eb1
hexbed6b0194d9

13114330420441 has 2 divisors, whose sum is σ = 13114330420442. Its totient is φ = 13114330420440.

The previous prime is 13114330420393. The next prime is 13114330420447. The reversal of 13114330420441 is 14402403341131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11577278451600 + 1537051968841 = 3402540^2 + 1239779^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114330420441 - 27 = 13114330420313 is a prime.

It is not a weakly prime, because it can be changed into another prime (13114330420447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557165210220 + 6557165210221.

It is an arithmetic number, because the mean of its divisors is an integer number (6557165210221).

Almost surely, 213114330420441 is an apocalyptic number.

It is an amenable number.

13114330420441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114330420441 is an equidigital number, since it uses as much as digits as its factorization.

13114330420441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13114330420441 its reverse (14402403341131), we get a palindrome (27516733761572).

The spelling of 13114330420441 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty million, four hundred twenty thousand, four hundred forty-one".