Base | Representation |
---|---|
bin | 1011111011010110101100… |
… | …0000011001010011011001 |
3 | 1201102201101020100122201211 |
4 | 2332311223000121103121 |
5 | 3204331122041423231 |
6 | 43520350142143121 |
7 | 2522323222214335 |
oct | 276655300312331 |
9 | 51381336318654 |
10 | 13114330420441 |
11 | 41a68356a5878 |
12 | 157978a881aa1 |
13 | 7418a3395c83 |
14 | 334a463b07c5 |
15 | 17b201a21eb1 |
hex | bed6b0194d9 |
13114330420441 has 2 divisors, whose sum is σ = 13114330420442. Its totient is φ = 13114330420440.
The previous prime is 13114330420393. The next prime is 13114330420447. The reversal of 13114330420441 is 14402403341131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11577278451600 + 1537051968841 = 3402540^2 + 1239779^2 .
It is a cyclic number.
It is not a de Polignac number, because 13114330420441 - 27 = 13114330420313 is a prime.
It is not a weakly prime, because it can be changed into another prime (13114330420447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557165210220 + 6557165210221.
It is an arithmetic number, because the mean of its divisors is an integer number (6557165210221).
Almost surely, 213114330420441 is an apocalyptic number.
It is an amenable number.
13114330420441 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114330420441 is an equidigital number, since it uses as much as digits as its factorization.
13114330420441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13114330420441 its reverse (14402403341131), we get a palindrome (27516733761572).
The spelling of 13114330420441 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty million, four hundred twenty thousand, four hundred forty-one".
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