1311433302041 has 2 divisors, whose sum is σ = 1311433302042. Its totient is φ = 1311433302040.

The previous prime is 1311433302001. The next prime is 1311433302043. The reversal of 1311433302041 is 1402033341131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1242379973641 + 69053328400 = 1114621^2 + 262780^2 .

It is an emirp because it is prime and its reverse (1402033341131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311433302041 is a prime.

Together with 1311433302043, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1311433302041.

It is not a weakly prime, because it can be changed into another prime (1311433302043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655716651020 + 655716651021.

It is an arithmetic number, because the mean of its divisors is an integer number (655716651021).

Almost surely, 2^{1311433302041} is an apocalyptic number.

It is an amenable number.

1311433302041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311433302041 is an equidigital number, since it uses as much as digits as its factorization.

1311433302041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 1311433302041 its reverse (1402033341131), we get a palindrome (2713466643172).

The spelling of 1311433302041 in words is "one trillion, three hundred eleven billion, four hundred thirty-three million, three hundred two thousand, forty-one".