Base | Representation |
---|---|
bin | 10011000101010111100… |
… | …001000010000000011110 |
3 | 11122101001001010101010111 |
4 | 103011113201002000132 |
5 | 132441303411131141 |
6 | 2442244131000234 |
7 | 163514353066450 |
oct | 23052741020036 |
9 | 4571031111114 |
10 | 1311433302046 |
11 | 4661a2a0124a |
12 | 1921b843907a |
13 | 9688aa2331a |
14 | 4768bc0c2d0 |
15 | 241a7a55381 |
hex | 1315784201e |
1311433302046 has 16 divisors (see below), whose sum is σ = 2320693032960. Its totient is φ = 543912429240.
The previous prime is 1311433302043. The next prime is 1311433302079. The reversal of 1311433302046 is 6402033341131.
It is a super-2 number, since 2×13114333020462 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a junction number, because it is equal to n+sod(n) for n = 1311433301999 and 1311433302017.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311433302041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1510867426 + ... + 1510868293.
It is an arithmetic number, because the mean of its divisors is an integer number (145043314560).
Almost surely, 21311433302046 is an apocalyptic number.
1311433302046 is a deficient number, since it is larger than the sum of its proper divisors (1009259730914).
1311433302046 is a wasteful number, since it uses less digits than its factorization.
1311433302046 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3021735759.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 1311433302046 its reverse (6402033341131), we get a palindrome (7713466643177).
The spelling of 1311433302046 in words is "one trillion, three hundred eleven billion, four hundred thirty-three million, three hundred two thousand, forty-six".
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