Base | Representation |
---|---|
bin | 1011111011010110101100… |
… | …1110000110101110000101 |
3 | 1201102201101111010020122020 |
4 | 2332311223032012232011 |
5 | 3204331124001424331 |
6 | 43520350351153353 |
7 | 2522323264603230 |
oct | 276655316065605 |
9 | 51381344106566 |
10 | 13114334014341 |
11 | 41a683772aa3a |
12 | 157978bb15859 |
13 | 7418a4053a41 |
14 | 334a46a68417 |
15 | 17b201ed1c96 |
hex | bed6b386b85 |
13114334014341 has 8 divisors (see below), whose sum is σ = 19983747069504. Its totient is φ = 7493905151040.
The previous prime is 13114334014337. The next prime is 13114334014357. The reversal of 13114334014341 is 14341043341131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13114334014341 - 22 = 13114334014337 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13114334014541) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 312246047940 + ... + 312246047981.
It is an arithmetic number, because the mean of its divisors is an integer number (2497968383688).
Almost surely, 213114334014341 is an apocalyptic number.
It is an amenable number.
13114334014341 is a deficient number, since it is larger than the sum of its proper divisors (6869413055163).
13114334014341 is an equidigital number, since it uses as much as digits as its factorization.
13114334014341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 624492095931.
The product of its (nonzero) digits is 20736, while the sum is 33.
Adding to 13114334014341 its reverse (14341043341131), we get a palindrome (27455377355472).
The spelling of 13114334014341 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty-four million, fourteen thousand, three hundred forty-one".
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