Base | Representation |
---|---|
bin | 1011111011010110101110… |
… | …0101101101011100111011 |
3 | 1201102201101220202121220212 |
4 | 2332311223211231130323 |
5 | 3204331132042433144 |
6 | 43520351131541335 |
7 | 2522323401315020 |
oct | 276655345553473 |
9 | 51381356677825 |
10 | 13114340202299 |
11 | 41a6840177056 |
12 | 1579791bba84b |
13 | 7418a540c45b |
14 | 334a477d9547 |
15 | 17b20280549e |
hex | bed6b96d73b |
13114340202299 has 4 divisors (see below), whose sum is σ = 14987817374064. Its totient is φ = 11240863030536.
The previous prime is 13114340202277. The next prime is 13114340202307. The reversal of 13114340202299 is 99220204341131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13114340202299 - 224 = 13114323425083 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13114340202239) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936738585872 + ... + 936738585885.
It is an arithmetic number, because the mean of its divisors is an integer number (3746954343516).
Almost surely, 213114340202299 is an apocalyptic number.
13114340202299 is a deficient number, since it is larger than the sum of its proper divisors (1873477171765).
13114340202299 is an equidigital number, since it uses as much as digits as its factorization.
13114340202299 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1873477171764.
The product of its (nonzero) digits is 93312, while the sum is 41.
The spelling of 13114340202299 in words is "thirteen trillion, one hundred fourteen billion, three hundred forty million, two hundred two thousand, two hundred ninety-nine".
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