Base | Representation |
---|---|
bin | 1011111011010110101110… |
… | …0101101101011100111100 |
3 | 1201102201101220202121220220 |
4 | 2332311223211231130330 |
5 | 3204331132042433200 |
6 | 43520351131541340 |
7 | 2522323401315021 |
oct | 276655345553474 |
9 | 51381356677826 |
10 | 13114340202300 |
11 | 41a6840177057 |
12 | 1579791bba850 |
13 | 7418a540c45c |
14 | 334a477d9548 |
15 | 17b2028054a0 |
hex | bed6b96d73c |
13114340202300 has 72 divisors (see below), whose sum is σ = 39941218598400. Its totient is φ = 3313096470720.
The previous prime is 13114340202277. The next prime is 13114340202307. The reversal of 13114340202300 is 320204341131.
It is a happy number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13114340202307) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1150375020 + ... + 1150386419.
It is an arithmetic number, because the mean of its divisors is an integer number (554739147200).
Almost surely, 213114340202300 is an apocalyptic number.
13114340202300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13114340202300 is an abundant number, since it is smaller than the sum of its proper divisors (26826878396100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13114340202300 is a wasteful number, since it uses less digits than its factorization.
13114340202300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2300761475 (or 2300761468 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 13114340202300 its reverse (320204341131), we get a palindrome (13434544543431).
The spelling of 13114340202300 in words is "thirteen trillion, one hundred fourteen billion, three hundred forty million, two hundred two thousand, three hundred".
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