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1311434062853 is a prime number
BaseRepresentation
bin10011000101010111100…
…011111011110000000101
311122101001002120000202112
4103011113203323300011
5132441304110002403
62442244155150405
7163514362415525
oct23052743736005
94571032500675
101311434062853
114661a3380912
121921b8745405
139688ac2b6c5
144768bd69685
15241a7b559d8
hex131578fbc05

1311434062853 has 2 divisors, whose sum is σ = 1311434062854. Its totient is φ = 1311434062852.

The previous prime is 1311434062769. The next prime is 1311434062859. The reversal of 1311434062853 is 3582604341131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1311407457889 + 26604964 = 1145167^2 + 5158^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311434062853 - 230 = 1310360321029 is a prime.

It is a super-2 number, since 2×13114340628532 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1311434062853.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311434062859) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655717031426 + 655717031427.

It is an arithmetic number, because the mean of its divisors is an integer number (655717031427).

Almost surely, 21311434062853 is an apocalyptic number.

It is an amenable number.

1311434062853 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311434062853 is an equidigital number, since it uses as much as digits as its factorization.

1311434062853 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 207360, while the sum is 41.

The spelling of 1311434062853 in words is "one trillion, three hundred eleven billion, four hundred thirty-four million, sixty-two thousand, eight hundred fifty-three".