1311440020441 has 4 divisors (see below), whose sum is σ = 1311444789732. Its totient is φ = 1311435251152.

The previous prime is 1311440020409. The next prime is 1311440020507. The reversal of 1311440020441 is 1440200441131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 899834371216 + 411605649225 = 948596^2 + 641565^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311440020441 - 2⁵ = 1311440020409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311440050441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1945186 + ... + 2531131.

It is an arithmetic number, because the mean of its divisors is an integer number (327861197433).

Almost surely, 2^{1311440020441} is an apocalyptic number.

It is an amenable number.

1311440020441 is a deficient number, since it is larger than the sum of its proper divisors (4769291).

1311440020441 is an equidigital number, since it uses as much as digits as its factorization.

1311440020441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4769290.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1311440020441 its reverse (1440200441131), we get a palindrome (2751640461572).

The spelling of 1311440020441 in words is "one trillion, three hundred eleven billion, four hundred forty million, twenty thousand, four hundred forty-one".