Base | Representation |
---|---|
bin | 1011111011010111000100… |
… | …0001001111010111001111 |
3 | 1201102201122021012010120011 |
4 | 2332311301001033113033 |
5 | 3204331323403231132 |
6 | 43520404144334051 |
7 | 2522325555553033 |
oct | 276656101172717 |
9 | 51381567163504 |
10 | 13114431305167 |
11 | 41a6887640a85 |
12 | 15797b8614327 |
13 | 7418bb25938a |
14 | 334a559521c3 |
15 | 17b20a7edb47 |
hex | bed7104f5cf |
13114431305167 has 2 divisors, whose sum is σ = 13114431305168. Its totient is φ = 13114431305166.
The previous prime is 13114431305111. The next prime is 13114431305203. The reversal of 13114431305167 is 76150313441131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13114431305167 - 239 = 12564675491279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114431305567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557215652583 + 6557215652584.
It is an arithmetic number, because the mean of its divisors is an integer number (6557215652584).
Almost surely, 213114431305167 is an apocalyptic number.
13114431305167 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114431305167 is an equidigital number, since it uses as much as digits as its factorization.
13114431305167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90720, while the sum is 40.
Adding to 13114431305167 its reverse (76150313441131), we get a palindrome (89264744746298).
The spelling of 13114431305167 in words is "thirteen trillion, one hundred fourteen billion, four hundred thirty-one million, three hundred five thousand, one hundred sixty-seven".
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