1311446255531 has 2 divisors, whose sum is σ = 1311446255532. Its totient is φ = 1311446255530.

The previous prime is 1311446255513. The next prime is 1311446255549. The reversal of 1311446255531 is 1355526441131.

Together with previous prime (1311446255513) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (1311446255513) and next prime (1311446255549).

It is a cyclic number.

It is not a de Polignac number, because 1311446255531 - 2¹⁰ = 1311446254507 is a prime.

It is a super-2 number, since 2×1311446255531² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1311446258531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655723127765 + 655723127766.

It is an arithmetic number, because the mean of its divisors is an integer number (655723127766).

Almost surely, 2^{1311446255531} is an apocalyptic number.

1311446255531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311446255531 is an equidigital number, since it uses as much as digits as its factorization.

1311446255531 is an evil number, because the sum of its binary digits is even.

The product of its digits is 216000, while the sum is 41.

The spelling of 1311446255531 in words is "one trillion, three hundred eleven billion, four hundred forty-six million, two hundred fifty-five thousand, five hundred thirty-one".