Base | Representation |
---|---|
bin | 10011000101011000100… |
… | …001100010100100000110 |
3 | 11122101002012221112001211 |
4 | 103011120201202210012 |
5 | 132441322223300424 |
6 | 2442245533242034 |
7 | 163514646610423 |
oct | 23053041424406 |
9 | 4571065845054 |
10 | 1311450212614 |
11 | 466201501423 |
12 | 19220203331a |
13 | 96891394489 |
14 | 47690170d4a |
15 | 241a9295b94 |
hex | 13158862906 |
1311450212614 has 4 divisors (see below), whose sum is σ = 1967175318924. Its totient is φ = 655725106306.
The previous prime is 1311450212609. The next prime is 1311450212627. The reversal of 1311450212614 is 4162120541131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327862553152 + ... + 327862553155.
It is an arithmetic number, because the mean of its divisors is an integer number (491793829731).
Almost surely, 21311450212614 is an apocalyptic number.
1311450212614 is a deficient number, since it is larger than the sum of its proper divisors (655725106310).
1311450212614 is an equidigital number, since it uses as much as digits as its factorization.
1311450212614 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 655725106309.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 1311450212614 its reverse (4162120541131), we get a palindrome (5473570753745).
The spelling of 1311450212614 in words is "one trillion, three hundred eleven billion, four hundred fifty million, two hundred twelve thousand, six hundred fourteen".
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