Base | Representation |
---|---|
bin | 11000011011011001… |
… | …11010111111010101 |
3 | 1020211222202221021211 |
4 | 30031230322333111 |
5 | 203324341003103 |
6 | 10005211141421 |
7 | 642665543011 |
oct | 141554727725 |
9 | 36758687254 |
10 | 13114781653 |
11 | 561aa52626 |
12 | 2660144871 |
13 | 13100bc63c |
14 | 8c5ac7541 |
15 | 51b57636d |
hex | 30db3afd5 |
13114781653 has 4 divisors (see below), whose sum is σ = 13116479680. Its totient is φ = 13113083628.
The previous prime is 13114781651. The next prime is 13114781717. The reversal of 13114781653 is 35618741131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13114781653 - 21 = 13114781651 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13114781651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 837375 + ... + 852892.
It is an arithmetic number, because the mean of its divisors is an integer number (3279119920).
Almost surely, 213114781653 is an apocalyptic number.
It is an amenable number.
13114781653 is a deficient number, since it is larger than the sum of its proper divisors (1698027).
13114781653 is an equidigital number, since it uses as much as digits as its factorization.
13114781653 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1698026.
The product of its digits is 60480, while the sum is 40.
It can be divided in two parts, 1311478 and 1653, that added together give a palindrome (1313131).
The spelling of 13114781653 in words is "thirteen billion, one hundred fourteen million, seven hundred eighty-one thousand, six hundred fifty-three".
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