Base | Representation |
---|---|
bin | 11101110100100000111010… |
… | …010101110010010001000111 |
3 | 122012101000111100200101202012 |
4 | 131310200322111302101013 |
5 | 114142244000113440403 |
6 | 1142534235410204435 |
7 | 36424266206261300 |
oct | 3564407225622107 |
9 | 565330440611665 |
10 | 131152100140103 |
11 | 38875325445649 |
12 | 128621a4b8371b |
13 | 5824789239a13 |
14 | 2455b1cc7b7a7 |
15 | 1026878e82ed8 |
hex | 77483a572447 |
131152100140103 has 24 divisors (see below), whose sum is σ = 162250020903600. Its totient is φ = 105401517193728.
The previous prime is 131152100140073. The next prime is 131152100140111. The reversal of 131152100140103 is 301041001251131.
It is not a de Polignac number, because 131152100140103 - 242 = 126754053628999 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131152100140133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 726055508 + ... + 726236121.
It is an arithmetic number, because the mean of its divisors is an integer number (6760417537650).
Almost surely, 2131152100140103 is an apocalyptic number.
131152100140103 is a deficient number, since it is larger than the sum of its proper divisors (31097920763497).
131152100140103 is a wasteful number, since it uses less digits than its factorization.
131152100140103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1452291759 (or 1452291752 counting only the distinct ones).
The product of its (nonzero) digits is 360, while the sum is 23.
Adding to 131152100140103 its reverse (301041001251131), we get a palindrome (432193101391234).
The spelling of 131152100140103 in words is "one hundred thirty-one trillion, one hundred fifty-two billion, one hundred million, one hundred forty thousand, one hundred three".
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