Base | Representation |
---|---|
bin | 111101000100101001… |
… | …1001100101011100111 |
3 | 110112112020121211202201 |
4 | 1322021103030223213 |
5 | 4122100021431101 |
6 | 140130045515331 |
7 | 12322040053366 |
oct | 1721123145347 |
9 | 415466554681 |
10 | 131152530151 |
11 | 50692203095 |
12 | 21502872b47 |
13 | c4a18b8436 |
14 | 64c259d7dd |
15 | 3629123e01 |
hex | 1e894ccae7 |
131152530151 has 4 divisors (see below), whose sum is σ = 131240025000. Its totient is φ = 131065035304.
The previous prime is 131152530133. The next prime is 131152530161. The reversal of 131152530151 is 151035251131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 151035251131 = 7549 ⋅20007319.
It is a cyclic number.
It is not a de Polignac number, because 131152530151 - 27 = 131152530023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131152530161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43745176 + ... + 43748173.
It is an arithmetic number, because the mean of its divisors is an integer number (32810006250).
Almost surely, 2131152530151 is an apocalyptic number.
131152530151 is a deficient number, since it is larger than the sum of its proper divisors (87494849).
131152530151 is an equidigital number, since it uses as much as digits as its factorization.
131152530151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87494848.
The product of its (nonzero) digits is 2250, while the sum is 28.
Adding to 131152530151 its reverse (151035251131), we get a palindrome (282187781282).
The spelling of 131152530151 in words is "one hundred thirty-one billion, one hundred fifty-two million, five hundred thirty thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •