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1311531230435 = 5262306246087
BaseRepresentation
bin10011000101011101010…
…110100110010011100011
311122101021212101122121212
4103011131112212103203
5132442003443333220
62442301545540335
7163516652343116
oct23053526462343
94571255348555
101311531230435
114662432082a8
121922251a46ab
13968a50bcc0a
144769ac2057d
15241b144b0c5
hex1315d5a64e3

1311531230435 has 4 divisors (see below), whose sum is σ = 1573837476528. Its totient is φ = 1049224984344.

The previous prime is 1311531230431. The next prime is 1311531230441. The reversal of 1311531230435 is 5340321351131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311531230435 - 22 = 1311531230431 is a prime.

It is a super-2 number, since 2×13115312304352 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311531230431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131153123039 + ... + 131153123048.

It is an arithmetic number, because the mean of its divisors is an integer number (393459369132).

Almost surely, 21311531230435 is an apocalyptic number.

1311531230435 is a deficient number, since it is larger than the sum of its proper divisors (262306246093).

1311531230435 is an equidigital number, since it uses as much as digits as its factorization.

1311531230435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262306246092.

The product of its (nonzero) digits is 16200, while the sum is 32.

Adding to 1311531230435 its reverse (5340321351131), we get a palindrome (6651852581566).

The spelling of 1311531230435 in words is "one trillion, three hundred eleven billion, five hundred thirty-one million, two hundred thirty thousand, four hundred thirty-five".

Divisors: 1 5 262306246087 1311531230435