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131153144423449 is a prime number
BaseRepresentation
bin11101110100100001111000…
…100101011010010000011001
3122012101010012010200111012011
4131310201320211122100121
5114142303114433022244
61142534531152545521
736424334116450201
oct3564417045322031
9565333163614164
10131153144423449
1138875810965135
12128624368522a1
1358248c46b0265
142455bbb835401
1510268da9b0434
hex77487895a419

131153144423449 has 2 divisors, whose sum is σ = 131153144423450. Its totient is φ = 131153144423448.

The previous prime is 131153144423437. The next prime is 131153144423593. The reversal of 131153144423449 is 944324441351131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87623921385225 + 43529223038224 = 9360765^2 + 6597668^2 .

It is a cyclic number.

It is not a de Polignac number, because 131153144423449 - 213 = 131153144415257 is a prime.

It is a super-2 number, since 2×1311531444234492 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131153144423149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65576572211724 + 65576572211725.

It is an arithmetic number, because the mean of its divisors is an integer number (65576572211725).

Almost surely, 2131153144423449 is an apocalyptic number.

It is an amenable number.

131153144423449 is a deficient number, since it is larger than the sum of its proper divisors (1).

131153144423449 is an equidigital number, since it uses as much as digits as its factorization.

131153144423449 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2488320, while the sum is 49.

The spelling of 131153144423449 in words is "one hundred thirty-one trillion, one hundred fifty-three billion, one hundred forty-four million, four hundred twenty-three thousand, four hundred forty-nine".