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131153144423593 is a prime number
BaseRepresentation
bin11101110100100001111000…
…100101011010010010101001
3122012101010012010200111101111
4131310201320211122102221
5114142303114433023333
61142534531152550321
736424334116450465
oct3564417045322251
9565333163614344
10131153144423593
1138875810965256
12128624368523a1
1358248c46b0346
142455bbb8354a5
1510268da9b04cd
hex77487895a4a9

131153144423593 has 2 divisors, whose sum is σ = 131153144423594. Its totient is φ = 131153144423592.

The previous prime is 131153144423449. The next prime is 131153144423617. The reversal of 131153144423593 is 395324441351131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 69514189725289 + 61638954698304 = 8337517^2 + 7851048^2 .

It is a cyclic number.

It is not a de Polignac number, because 131153144423593 - 233 = 131144554489001 is a prime.

It is a super-2 number, since 2×1311531444235932 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131153144424593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65576572211796 + 65576572211797.

It is an arithmetic number, because the mean of its divisors is an integer number (65576572211797).

Almost surely, 2131153144423593 is an apocalyptic number.

It is an amenable number.

131153144423593 is a deficient number, since it is larger than the sum of its proper divisors (1).

131153144423593 is an equidigital number, since it uses as much as digits as its factorization.

131153144423593 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2332800, while the sum is 49.

The spelling of 131153144423593 in words is "one hundred thirty-one trillion, one hundred fifty-three billion, one hundred forty-four million, four hundred twenty-three thousand, five hundred ninety-three".