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131153522053 = 663011978153
BaseRepresentation
bin111101000100101011…
…0111110110110000101
3110112112022111020101211
41322021112332312011
54122100300201203
6140130123051421
712322051354261
oct1721126766605
9415468436354
10131153522053
1150692820344
1221503070b71
13c4a1b74a68
1464c277b0a1
15362926cc6d
hex1e895bed85

131153522053 has 4 divisors (see below), whose sum is σ = 131155566508. Its totient is φ = 131151477600.

The previous prime is 131153522051. The next prime is 131153522077. The reversal of 131153522053 is 350225351131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 39064336609 + 92089185444 = 197647^2 + 303462^2 .

It is a cyclic number.

It is not a de Polignac number, because 131153522053 - 21 = 131153522051 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131153522051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 922776 + ... + 1055377.

It is an arithmetic number, because the mean of its divisors is an integer number (32788891627).

Almost surely, 2131153522053 is an apocalyptic number.

It is an amenable number.

131153522053 is a deficient number, since it is larger than the sum of its proper divisors (2044455).

131153522053 is an equidigital number, since it uses as much as digits as its factorization.

131153522053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2044454.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 131153522053 its reverse (350225351131), we get a palindrome (481378873184).

The spelling of 131153522053 in words is "one hundred thirty-one billion, one hundred fifty-three million, five hundred twenty-two thousand, fifty-three".

Divisors: 1 66301 1978153 131153522053