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13115394503 is a prime number
BaseRepresentation
bin11000011011011110…
…10000100111000111
31020212000221001221222
430031233100213013
5203330020111003
610005232230555
7643004004521
oct141557204707
936760831858
1013115394503
115620331012
12266039b45b
131310275583
148c5c06a11
1551b647c38
hex30dbd09c7

13115394503 has 2 divisors, whose sum is σ = 13115394504. Its totient is φ = 13115394502.

The previous prime is 13115394497. The next prime is 13115394553. The reversal of 13115394503 is 30549351131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13115394503 - 28 = 13115394247 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13115394553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557697251 + 6557697252.

It is an arithmetic number, because the mean of its divisors is an integer number (6557697252).

Almost surely, 213115394503 is an apocalyptic number.

13115394503 is a deficient number, since it is larger than the sum of its proper divisors (1).

13115394503 is an equidigital number, since it uses as much as digits as its factorization.

13115394503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24300, while the sum is 35.

The spelling of 13115394503 in words is "thirteen billion, one hundred fifteen million, three hundred ninety-four thousand, five hundred three".