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13115401451 = 171696345481
BaseRepresentation
bin11000011011011110…
…10010010011101011
31020212000221102111022
430031233102103223
5203330020321301
610005232323055
7643004034005
oct141557222353
936760842438
1013115401451
115620336259
1226603a348b
131310278799
148c5c09375
1551b649d1b
hex30dbd24eb

13115401451 has 8 divisors (see below), whose sum is σ = 13888019664. Its totient is φ = 12342908160.

The previous prime is 13115401423. The next prime is 13115401459. The reversal of 13115401451 is 15410451131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13115401451 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13115401451.

It is not an unprimeable number, because it can be changed into a prime (13115401459) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 265631 + ... + 311111.

It is an arithmetic number, because the mean of its divisors is an integer number (1736002458).

Almost surely, 213115401451 is an apocalyptic number.

13115401451 is a deficient number, since it is larger than the sum of its proper divisors (772618213).

13115401451 is a wasteful number, since it uses less digits than its factorization.

13115401451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62461.

The product of its (nonzero) digits is 1200, while the sum is 26.

Adding to 13115401451 its reverse (15410451131), we get a palindrome (28525852582).

The spelling of 13115401451 in words is "thirteen billion, one hundred fifteen million, four hundred one thousand, four hundred fifty-one".

Divisors: 1 17 16963 45481 288371 773177 771494203 13115401451