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13115504933 is a prime number
BaseRepresentation
bin11000011011011111…
…01011100100100101
31020212001010200102222
430031233223210211
5203330032124213
610005234442125
7643004644466
oct141557534445
936761120388
1013115504933
1156203a6a83
122660433345
1313102b390b
148c5c34d6d
1551b66a808
hex30dbeb925

13115504933 has 2 divisors, whose sum is σ = 13115504934. Its totient is φ = 13115504932.

The previous prime is 13115504929. The next prime is 13115505031. The reversal of 13115504933 is 33940551131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13094911489 + 20593444 = 114433^2 + 4538^2 .

It is an emirp because it is prime and its reverse (33940551131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13115504933 - 22 = 13115504929 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13115504893 and 13115504902.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13115501933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557752466 + 6557752467.

It is an arithmetic number, because the mean of its divisors is an integer number (6557752467).

Almost surely, 213115504933 is an apocalyptic number.

It is an amenable number.

13115504933 is a deficient number, since it is larger than the sum of its proper divisors (1).

13115504933 is an equidigital number, since it uses as much as digits as its factorization.

13115504933 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24300, while the sum is 35.

The spelling of 13115504933 in words is "thirteen billion, one hundred fifteen million, five hundred four thousand, nine hundred thirty-three".