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13115604992000 = 217537217312
BaseRepresentation
bin1011111011011011011011…
…1110100000000000000000
31201102211200001200121012212
42332312312332200000000
53204341224334221000
643521120432441252
72522366626666400
oct276666676400000
951384601617185
1013115604992000
1141a732a1052a5
121579a856a9228
13741a47469a24
14334b27792800
1517b27888cc35
hexbedb6fa0000

13115604992000 has 1296 divisors, whose sum is σ = 41663857087944. Its totient is φ = 4095737856000.

The previous prime is 13115604991981. The next prime is 13115604992011. The reversal of 13115604992000 is 29940651131.

It can be written as a sum of positive squares in 4 ways, for example, as 5706059677696 + 7409545314304 = 2388736^2 + 2722048^2 .

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 423084031985 + ... + 423084032015.

Almost surely, 213115604992000 is an apocalyptic number.

13115604992000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13115604992000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20831928543972).

13115604992000 is an abundant number, since it is smaller than the sum of its proper divisors (28548252095944).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13115604992000 is an frugal number, since it uses more digits than its factorization.

13115604992000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 142 (or 62 counting only the distinct ones).

The product of its (nonzero) digits is 58320, while the sum is 41.

The spelling of 13115604992000 in words is "thirteen trillion, one hundred fifteen billion, six hundred four million, nine hundred ninety-two thousand".