Base | Representation |
---|---|
bin | 11000011011100001… |
… | …11001111100010011 |
3 | 1020212001201222210002 |
4 | 30031300321330103 |
5 | 203330122412224 |
6 | 10005245400215 |
7 | 643010452406 |
oct | 141560717423 |
9 | 36761658702 |
10 | 13115825939 |
11 | 56205a6177 |
12 | 266056906b |
13 | 1310396a68 |
14 | 8c5cb9d3d |
15 | 51b6d09ae |
hex | 30dc39f13 |
13115825939 has 2 divisors, whose sum is σ = 13115825940. Its totient is φ = 13115825938.
The previous prime is 13115825857. The next prime is 13115825993. The reversal of 13115825939 is 93952851131.
It is a happy number.
Together with next prime (13115825993) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13115825939 - 28 = 13115825683 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13115825893 and 13115825902.
It is not a weakly prime, because it can be changed into another prime (13115855939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557912969 + 6557912970.
It is an arithmetic number, because the mean of its divisors is an integer number (6557912970).
Almost surely, 213115825939 is an apocalyptic number.
13115825939 is a deficient number, since it is larger than the sum of its proper divisors (1).
13115825939 is an equidigital number, since it uses as much as digits as its factorization.
13115825939 is an evil number, because the sum of its binary digits is even.
The product of its digits is 291600, while the sum is 47.
The spelling of 13115825939 in words is "thirteen billion, one hundred fifteen million, eight hundred twenty-five thousand, nine hundred thirty-nine".
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