1311614230541 has 4 divisors (see below), whose sum is σ = 1328216942400. Its totient is φ = 1295011518684.

The previous prime is 1311614230517. The next prime is 1311614230609. The reversal of 1311614230541 is 1450324161131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311614230541 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311614230498 and 1311614230507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311614230741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8301355811 + ... + 8301355968.

It is an arithmetic number, because the mean of its divisors is an integer number (332054235600).

Almost surely, 2^{1311614230541} is an apocalyptic number.

It is an amenable number.

1311614230541 is a deficient number, since it is larger than the sum of its proper divisors (16602711859).

1311614230541 is an equidigital number, since it uses as much as digits as its factorization.

1311614230541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16602711858.

The product of its (nonzero) digits is 8640, while the sum is 32.

Adding to 1311614230541 its reverse (1450324161131), we get a palindrome (2761938391672).

The spelling of 1311614230541 in words is "one trillion, three hundred eleven billion, six hundred fourteen million, two hundred thirty thousand, five hundred forty-one".