Base | Representation |
---|---|
bin | 10011000101100010011… |
… | …010000100000000110111 |
3 | 11122101111202221122101122 |
4 | 103011202122010000313 |
5 | 132442142200242011 |
6 | 2442314215214155 |
7 | 163522032154403 |
oct | 23054232040067 |
9 | 4571452848348 |
10 | 1311616024631 |
11 | 466287063450 |
12 | 19224967735b |
13 | 968b983b4b3 |
14 | 476a81b4103 |
15 | 241b8aea3db |
hex | 13162684037 |
1311616024631 has 16 divisors (see below), whose sum is σ = 1525227302400. Its totient is φ = 1115322436800.
The previous prime is 1311616024531. The next prime is 1311616024637. The reversal of 1311616024631 is 1364206161131.
It is not a de Polignac number, because 1311616024631 - 210 = 1311616023607 is a prime.
It is a super-2 number, since 2×13116160246312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1311616024591 and 1311616024600.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311616024637) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39702950 + ... + 39735971.
It is an arithmetic number, because the mean of its divisors is an integer number (95326706400).
Almost surely, 21311616024631 is an apocalyptic number.
1311616024631 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1311616024631 is a deficient number, since it is larger than the sum of its proper divisors (213611277769).
1311616024631 is a wasteful number, since it uses less digits than its factorization.
1311616024631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79439030.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 1311616024631 in words is "one trillion, three hundred eleven billion, six hundred sixteen million, twenty-four thousand, six hundred thirty-one".
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