Base | Representation |
---|---|
bin | 1011111011011110000010… |
… | …0000000000101101101011 |
3 | 1201102220110121120010012001 |
4 | 2332313200200000231223 |
5 | 3204344141210030403 |
6 | 43521313520231431 |
7 | 2522423116300615 |
oct | 276674040005553 |
9 | 51386417503161 |
10 | 13116301642603 |
11 | 41a76573771a5 |
12 | 157a03aa6b577 |
13 | 741b288a5713 |
14 | 334b920d7db5 |
15 | 17b2b9aecc1d |
hex | bede0800b6b |
13116301642603 has 4 divisors (see below), whose sum is σ = 13686575627088. Its totient is φ = 12546027658120.
The previous prime is 13116301642559. The next prime is 13116301642627. The reversal of 13116301642603 is 30624610361131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13116301642603 - 225 = 13116268088171 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13116301642903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285136992208 + ... + 285136992253.
It is an arithmetic number, because the mean of its divisors is an integer number (3421643906772).
Almost surely, 213116301642603 is an apocalyptic number.
13116301642603 is a deficient number, since it is larger than the sum of its proper divisors (570273984485).
13116301642603 is an equidigital number, since it uses as much as digits as its factorization.
13116301642603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 570273984484.
The product of its (nonzero) digits is 46656, while the sum is 37.
The spelling of 13116301642603 in words is "thirteen trillion, one hundred sixteen billion, three hundred one million, six hundred forty-two thousand, six hundred three".
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