13116430715361 has 4 divisors (see below), whose sum is σ = 17488574287152. Its totient is φ = 8744287143572.

The previous prime is 13116430715329. The next prime is 13116430715363. The reversal of 13116430715361 is 16351703461131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13116430715361 - 2⁵ = 13116430715329 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13116430715363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2186071785891 + ... + 2186071785896.

It is an arithmetic number, because the mean of its divisors is an integer number (4372143571788).

Almost surely, 2^{13116430715361} is an apocalyptic number.

It is an amenable number.

13116430715361 is a deficient number, since it is larger than the sum of its proper divisors (4372143571791).

13116430715361 is an equidigital number, since it uses as much as digits as its factorization.

13116430715361 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4372143571790.

The product of its (nonzero) digits is 136080, while the sum is 42.

The spelling of 13116430715361 in words is "thirteen trillion, one hundred sixteen billion, four hundred thirty million, seven hundred fifteen thousand, three hundred sixty-one".