Base | Representation |
---|---|
bin | 11000011011101011… |
… | …10001111101100011 |
3 | 1020212011010220220121 |
4 | 30031311301331203 |
5 | 203330434311341 |
6 | 10005333021111 |
7 | 643024354426 |
oct | 141565617543 |
9 | 36764126817 |
10 | 13117103971 |
11 | 56212993a4 |
12 | 2660a84797 |
13 | 13107236aa |
14 | 8c612d9bd |
15 | 51b8844d1 |
hex | 30dd71f63 |
13117103971 has 2 divisors, whose sum is σ = 13117103972. Its totient is φ = 13117103970.
The previous prime is 13117103969. The next prime is 13117104029. The reversal of 13117103971 is 17930171131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13117103971 - 21 = 13117103969 is a prime.
It is a super-3 number, since 3×131171039713 (a number of 31 digits) contains 333 as substring.
Together with 13117103969, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13117103371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6558551985 + 6558551986.
It is an arithmetic number, because the mean of its divisors is an integer number (6558551986).
Almost surely, 213117103971 is an apocalyptic number.
13117103971 is a deficient number, since it is larger than the sum of its proper divisors (1).
13117103971 is an equidigital number, since it uses as much as digits as its factorization.
13117103971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3969, while the sum is 34.
The spelling of 13117103971 in words is "thirteen billion, one hundred seventeen million, one hundred three thousand, nine hundred seventy-one".
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