1311819651050 has 12 divisors (see below), whose sum is σ = 2439984551046. Its totient is φ = 524727860400.

The previous prime is 1311819651019. The next prime is 1311819651091. The reversal of 1311819651050 is 501569181131.

It can be written as a sum of positive squares in 3 ways, for example, as 629710492849 + 682109158201 = 793543^2 + 825899^2 .

It is a super-2 number, since 2×1311819651050² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311819650989 and 1311819651007.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 13118196461 + ... + 13118196560.

Almost surely, 2^{1311819651050} is an apocalyptic number.

1311819651050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1311819651050 is a deficient number, since it is larger than the sum of its proper divisors (1128164899996).

1311819651050 is a wasteful number, since it uses less digits than its factorization.

1311819651050 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26236393033 (or 26236393028 counting only the distinct ones).

The product of its (nonzero) digits is 32400, while the sum is 41.

The spelling of 1311819651050 in words is "one trillion, three hundred eleven billion, eight hundred nineteen million, six hundred fifty-one thousand, fifty".