Base | Representation |
---|---|
bin | 10011000101110010010… |
… | …111100111110101101010 |
3 | 11122102012102212002010020 |
4 | 103011302113213311222 |
5 | 132443214224223034 |
6 | 2442400543101310 |
7 | 163531463325150 |
oct | 23056227476552 |
9 | 4572172762106 |
10 | 1311883820394 |
11 | 466404241364 |
12 | 1923032a1836 |
13 | 96930171c24 |
14 | 476d19a33d0 |
15 | 241d2397249 |
hex | 131725e7d6a |
1311883820394 has 32 divisors (see below), whose sum is σ = 3001692604416. Its totient is φ = 374436321840.
The previous prime is 1311883820371. The next prime is 1311883820399. The reversal of 1311883820394 is 4930283881131.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1311883820399) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16110022 + ... + 16191249.
It is an arithmetic number, because the mean of its divisors is an integer number (93802893888).
Almost surely, 21311883820394 is an apocalyptic number.
1311883820394 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1311883820394 is an abundant number, since it is smaller than the sum of its proper divisors (1689808784022).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311883820394 is a wasteful number, since it uses less digits than its factorization.
1311883820394 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32302250.
The product of its (nonzero) digits is 995328, while the sum is 51.
The spelling of 1311883820394 in words is "one trillion, three hundred eleven billion, eight hundred eighty-three million, eight hundred twenty thousand, three hundred ninety-four".
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