Base | Representation |
---|---|
bin | 1111101000111… |
… | …01000111110011 |
3 | 100010212012121102 |
4 | 13310131013303 |
5 | 232041110113 |
6 | 21003515015 |
7 | 3152051606 |
oct | 764350763 |
9 | 303765542 |
10 | 131191283 |
11 | 68065a53 |
12 | 37b28a6b |
13 | 21244aa2 |
14 | 135d033d |
15 | b7b6758 |
hex | 7d1d1f3 |
131191283 has 2 divisors, whose sum is σ = 131191284. Its totient is φ = 131191282.
The previous prime is 131191259. The next prime is 131191301. The reversal of 131191283 is 382191131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131191283 is a prime.
It is a super-2 number, since 2×1311912832 = 34422305470372178, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131191243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65595641 + 65595642.
It is an arithmetic number, because the mean of its divisors is an integer number (65595642).
Almost surely, 2131191283 is an apocalyptic number.
131191283 is a deficient number, since it is larger than the sum of its proper divisors (1).
131191283 is an equidigital number, since it uses as much as digits as its factorization.
131191283 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1296, while the sum is 29.
The square root of 131191283 is about 11453.8763307450. The cubic root of 131191283 is about 508.1223833005.
The spelling of 131191283 in words is "one hundred thirty-one million, one hundred ninety-one thousand, two hundred eighty-three".
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