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13119610913573 is a prime number
BaseRepresentation
bin1011111011101010010110…
…1111111000001100100101
31201110020000020112111112112
42332322211233320030211
53204422430343213243
643523022133330405
72522601121525133
oct276724557701445
951406006474475
1013119610913573
1141a8aa537348a
12157a803196a05
13742235382818
14334dc7808753
1517b4103d2818
hexbeea5bf8325

13119610913573 has 2 divisors, whose sum is σ = 13119610913574. Its totient is φ = 13119610913572.

The previous prime is 13119610913503. The next prime is 13119610913597. The reversal of 13119610913573 is 37531901691131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12317165814724 + 802445098849 = 3509582^2 + 895793^2 .

It is an emirp because it is prime and its reverse (37531901691131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13119610913573 - 216 = 13119610848037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13119610913503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6559805456786 + 6559805456787.

It is an arithmetic number, because the mean of its divisors is an integer number (6559805456787).

Almost surely, 213119610913573 is an apocalyptic number.

It is an amenable number.

13119610913573 is a deficient number, since it is larger than the sum of its proper divisors (1).

13119610913573 is an equidigital number, since it uses as much as digits as its factorization.

13119610913573 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 459270, while the sum is 50.

The spelling of 13119610913573 in words is "thirteen trillion, one hundred nineteen billion, six hundred ten million, nine hundred thirteen thousand, five hundred seventy-three".