131200011100127 has 2 divisors, whose sum is σ = 131200011100128. Its totient is φ = 131200011100126.

The previous prime is 131200011100069. The next prime is 131200011100157. The reversal of 131200011100127 is 721001110002131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131200011100127 - 2¹² = 131200011096031 is a prime.

It is a super-2 number, since 2×131200011100127² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131200011100099 and 131200011100108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131200011100157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600005550063 + 65600005550064.

It is an arithmetic number, because the mean of its divisors is an integer number (65600005550064).

Almost surely, 2^{131200011100127} is an apocalyptic number.

131200011100127 is a deficient number, since it is larger than the sum of its proper divisors (1).

131200011100127 is an equidigital number, since it uses as much as digits as its factorization.

131200011100127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 20.

Adding to 131200011100127 its reverse (721001110002131), we get a palindrome (852201121102258).

The spelling of 131200011100127 in words is "one hundred thirty-one trillion, two hundred billion, eleven million, one hundred thousand, one hundred twenty-seven".