131200011100131 has 4 divisors (see below), whose sum is σ = 174933348133512. Its totient is φ = 87466674066752.

The previous prime is 131200011100127. The next prime is 131200011100157. The reversal of 131200011100131 is 131001110002131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131200011100131 - 2² = 131200011100127 is a prime.

It is a super-2 number, since 2×131200011100131² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131200011100131.

It is not an unprimeable number, because it can be changed into a prime (131200011100531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21866668516686 + ... + 21866668516691.

It is an arithmetic number, because the mean of its divisors is an integer number (43733337033378).

Almost surely, 2^{131200011100131} is an apocalyptic number.

131200011100131 is a deficient number, since it is larger than the sum of its proper divisors (43733337033381).

131200011100131 is an equidigital number, since it uses as much as digits as its factorization.

131200011100131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43733337033380.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 131200011100131 its reverse (131001110002131), we get a palindrome (262201121102262).

The spelling of 131200011100131 in words is "one hundred thirty-one trillion, two hundred billion, eleven million, one hundred thousand, one hundred thirty-one".