1312000113133 has 2 divisors, whose sum is σ = 1312000113134. Its totient is φ = 1312000113132.

The previous prime is 1312000113113. The next prime is 1312000113139. The reversal of 1312000113133 is 3313110002131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 986720382244 + 325279730889 = 993338^2 + 570333^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1312000113133 is a prime.

It is a super-2 number, since 2×1312000113133² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1312000113133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312000113139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656000056566 + 656000056567.

It is an arithmetic number, because the mean of its divisors is an integer number (656000056567).

Almost surely, 2^{1312000113133} is an apocalyptic number.

It is an amenable number.

1312000113133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312000113133 is an equidigital number, since it uses as much as digits as its factorization.

1312000113133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1312000113133 its reverse (3313110002131), we get a palindrome (4625110115264).

The spelling of 1312000113133 in words is "one trillion, three hundred twelve billion, one hundred thirteen thousand, one hundred thirty-three".