Base | Representation |
---|---|
bin | 11101110101001101100111… |
… | …011011010101100011010011 |
3 | 122012112121101122011102012202 |
4 | 131311031213123111203103 |
5 | 114144040301402212243 |
6 | 1143012254443513415 |
7 | 36430615546530365 |
oct | 3565154733254323 |
9 | 565477348142182 |
10 | 131200101210323 |
11 | 38893717832112 |
12 | 1286b56052886b |
13 | 5829168b18552 |
14 | 2458193d10d35 |
15 | 1027c380c74b8 |
hex | 7753676d58d3 |
131200101210323 has 2 divisors, whose sum is σ = 131200101210324. Its totient is φ = 131200101210322.
The previous prime is 131200101210317. The next prime is 131200101210331. The reversal of 131200101210323 is 323012101002131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131200101210323 - 210 = 131200101209299 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131200101210295 and 131200101210304.
It is not a weakly prime, because it can be changed into another prime (131200101216323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600050605161 + 65600050605162.
It is an arithmetic number, because the mean of its divisors is an integer number (65600050605162).
Almost surely, 2131200101210323 is an apocalyptic number.
131200101210323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131200101210323 is an equidigital number, since it uses as much as digits as its factorization.
131200101210323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 131200101210323 its reverse (323012101002131), we get a palindrome (454212202212454).
The spelling of 131200101210323 in words is "one hundred thirty-one trillion, two hundred billion, one hundred one million, two hundred ten thousand, three hundred twenty-three".
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