13120110001 has 2 divisors, whose sum is σ = 13120110002. Its totient is φ = 13120110000.

The previous prime is 13120109993. The next prime is 13120110049. The reversal of 13120110001 is 10001102131.

13120110001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12780076401 + 340033600 = 113049^2 + 18440^2 .

It is an emirp because it is prime and its reverse (10001102131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13120110001 - 2³ = 13120109993 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13120110001.

It is not a weakly prime, because it can be changed into another prime (13120110061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560055000 + 6560055001.

It is an arithmetic number, because the mean of its divisors is an integer number (6560055001).

Almost surely, 2^13120110001 is an apocalyptic number.

It is an amenable number.

13120110001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13120110001 is an equidigital number, since it uses as much as digits as its factorization.

13120110001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 13120110001 its reverse (10001102131), we get a palindrome (23121212132).

The spelling of 13120110001 in words is "thirteen billion, one hundred twenty million, one hundred ten thousand, one".