Base | Representation |
---|---|
bin | 11101110101001110100100… |
… | …110101010111001101001100 |
3 | 122012112201001102201122210022 |
4 | 131311032210311113031030 |
5 | 114144044404122134040 |
6 | 1143012545005201312 |
7 | 36430653226416302 |
oct | 3565164465271514 |
9 | 565481042648708 |
10 | 131201131443020 |
11 | 388940a63251a1 |
12 | 1286b7a9560238 |
13 | 58292a13ac5b2 |
14 | 2458250a8c272 |
15 | 1027c9877b6b5 |
hex | 7753a4d5734c |
131201131443020 has 24 divisors (see below), whose sum is σ = 275782057861968. Its totient is φ = 52430989371200.
The previous prime is 131201131443001. The next prime is 131201131443047. The reversal of 131201131443020 is 20344131102131.
It is a super-2 number, since 2×1312011314430202 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3091428626 + ... + 3091471065.
It is an arithmetic number, because the mean of its divisors is an integer number (11490919077582).
Almost surely, 2131201131443020 is an apocalyptic number.
131201131443020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131201131443020 is an abundant number, since it is smaller than the sum of its proper divisors (144580926418948).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131201131443020 is a wasteful number, since it uses less digits than its factorization.
131201131443020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6182900761 (or 6182900759 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 131201131443020 its reverse (20344131102131), we get a palindrome (151545262545151).
The spelling of 131201131443020 in words is "one hundred thirty-one trillion, two hundred one billion, one hundred thirty-one million, four hundred forty-three thousand, twenty".
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