13120114120040 has 256 divisors, whose sum is σ = 30753064627200. Its totient is φ = 5033697177600.

The previous prime is 13120114120021. The next prime is 13120114120123. The reversal of 13120114120040 is 4002141102131.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13120114119994 and 13120114120021.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 19379784182 + ... + 19379784858.

It is an arithmetic number, because the mean of its divisors is an integer number (120129158700).

Almost surely, 2^{13120114120040} is an apocalyptic number.

13120114120040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13120114120040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15376532313600).

13120114120040 is an abundant number, since it is smaller than the sum of its proper divisors (17632950507160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13120114120040 is a wasteful number, since it uses less digits than its factorization.

13120114120040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1436 (or 1432 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 13120114120040 its reverse (4002141102131), we get a palindrome (17122255222171).

The spelling of 13120114120040 in words is "thirteen trillion, one hundred twenty billion, one hundred fourteen million, one hundred twenty thousand, forty".