131201141213333 has 4 divisors (see below), whose sum is σ = 131328397413408. Its totient is φ = 131073885013260.

The previous prime is 131201141213321. The next prime is 131201141213407. The reversal of 131201141213333 is 333312141102131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131201141213333 - 2³⁰ = 131200067471509 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131201141213296 and 131201141213305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131201141216333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63628098491 + ... + 63628100552.

It is an arithmetic number, because the mean of its divisors is an integer number (32832099353352).

Almost surely, 2^{131201141213333} is an apocalyptic number.

It is an amenable number.

131201141213333 is a deficient number, since it is larger than the sum of its proper divisors (127256200075).

131201141213333 is a wasteful number, since it uses less digits than its factorization.

131201141213333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 127256200074.

The product of its (nonzero) digits is 3888, while the sum is 29.

Adding to 131201141213333 its reverse (333312141102131), we get a palindrome (464513282315464).

The spelling of 131201141213333 in words is "one hundred thirty-one trillion, two hundred one billion, one hundred forty-one million, two hundred thirteen thousand, three hundred thirty-three".