131201141312133 has 48 divisors (see below), whose sum is σ = 200743909766400. Its totient is φ = 85593353412096.

The previous prime is 131201141312083. The next prime is 131201141312149. The reversal of 131201141312133 is 331213141102131.

131201141312133 is a `hidden beast` number, since 1 + 3 + 1 + 20 + 11 + 413 + 1 + 213 + 3 = 666.

It is not a de Polignac number, because 131201141312133 - 2¹⁸ = 131201141049989 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131201141312097 and 131201141312106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131201141312233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 74242593 + ... + 75989241.

It is an arithmetic number, because the mean of its divisors is an integer number (4182164786800).

Almost surely, 2^{131201141312133} is an apocalyptic number.

It is an amenable number.

131201141312133 is a deficient number, since it is larger than the sum of its proper divisors (69542768454267).

131201141312133 is an equidigital number, since it uses as much as digits as its factorization.

131201141312133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1753288 (or 1753276 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 27.

Adding to 131201141312133 its reverse (331213141102131), we get a palindrome (462414282414264).

The spelling of 131201141312133 in words is "one hundred thirty-one trillion, two hundred one billion, one hundred forty-one million, three hundred twelve thousand, one hundred thirty-three".